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mel-nik [20]
3 years ago
10

Vghfthcnbvhghvngjgjvjgkb, kcnjc cnnfjdhd mc Dan Jfhjc cm. Cm n n hdjfjocnkcnd

Computers and Technology
2 answers:
seropon [69]3 years ago
6 0

Is this supposed to be a question?

Alexxandr [17]3 years ago
4 0

The Answer is lkwnnewkk,ekcrcomciibfwxdmfcxechiuhfcmiuhrichihrf ubfbfb f e v fv v v fvfvfvfvfv fvfvffv

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You have a host device with an assigned IP address of 192.168.15.100 and a subnet mask of 255.255.255.192. To what network does
aalyn [17]

The options are missing from the question.

Below are the options.

A) 192.168.15.0

B) 192.168.15.16

C) 192.168.15.32

D) 192.168.15.64

Answer: The correct option to the question is option D

192.168.15.64

Explanation:

The Network is: 192.168.15.64/26 11000000.10101000.00001111.01000000

Then the Broadcast is: 192.168.15.127 11000000.10101000.00001111.01111111

We see the HostMin as: 192.168.15.65 11000000.10101000.00001111.01000001

And the HostMax as: 192.168.15.126 11000000.10101000.00001111.01111110

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3 years ago
Why is graphics important in multimedia application <br>​
erastova [34]
Graphics are important in multimedia application this is because humans are visually oriented etc.
5 0
3 years ago
Which statement will remove 5:'softball' from the dictionary?
dimaraw [331]

Answer:

sports.pop(5)

Explanation:

edg 2020

4 0
3 years ago
Read 2 more answers
Define a void function that calculates the sum (+), difference (-), product (*), quotient (/), and modulus (%) of two integer nu
BabaBlast [244]

Answer:

#include <iostream>

using namespace std;

void multipurpose(int &num1,int &num2,int &add,int &subt,int &multi,int &divi,int &modulo )

{

   add=num1+num2;//adding two numbers...

   subt=abs(num1-num2);//subtracting two numbers...

   multi=num1*num2;//multiplying two numbers...

   divi=num1/num2;//Finding quotient of two numbers...

   modulo=num1%num2;//Finding modulo of two numbers...

}

void print(int add,int sub,int divi,int multi,int modulo) //function to print the values.

{

   cout<<"The addition is "<<add<<endl<<"The subtraction is "<<sub<<endl

   <<"The quotient is "<<divi<<endl<<"The multiplication is "<<multi<<endl

   <<"The modulus is "<<modulo<<endl;

}

int main() {

   int a,b,sum=0,mult=0,divi=0,sub=0,modulo=0;

   cin>>a>>b;

   multipurpose(a,b,sum,sub,mult,divi,modulo);

   print(sum,sub,divi,mult,modulo);

return 0;

}

Enter the numbers

12 12

The addition is 24

The subtraction is 0

The quotient is 1

The multiplication is 144

The modulus is 0

Explanation:

I have created a function multipurpose that has a argument list of two numbers ,and variables for addition,subtraction,multiplication,Division,Modulus and these all are passed by reference.Since the function is of type void so it cannot return anything so the only way to store the result is by passing the variables to store the results by  reference.

The other function print has the arguments of all the results here you can pass them by value or by reference because you only need to print the results.

7 0
3 years ago
what is the best book or website to learn mechanical machine design? . high detail ,easy to under stand .
Vadim26 [7]
WERE IS A B C D I CANT GIVE YOU ANSWER
7 0
3 years ago
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