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3 years ago

I need help thank you

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

4 0

Answer:

≈ 5

Step-by-step explanation:

You can use the Pythagorean Theorem to solve this:

$a^{2} + b^{2} = c^{2}$

Now plug in the numbers into the formula:

$6^{2} + b^{2} = 8^{2}$

36 + $b^{2}$ = 64

Subtract 36 from both sides:

36 + $b^{2}$ = 64

-36 -36

_________

$b^{2}$ = 28

Square both sides:

$\sqrt{b^2} = \sqrt{28}$

b = 5.29

b ≈ 5

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18+6/-4-16 HELP only d part

Ivahew [28]

Answer:

$\frac{1}{2}$ is the answer

Step-by-step explanation:

First we need to substitute X and Y with their respective numbers

$3\cdot \:6+\frac{6}{-4}-\left(-4\right)^2$

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2 years ago

Read 2 more answers

How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?

shutvik [7]

Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

∴ 0.2x+0.8y=42

∴ 2x+8y=420

We get two linear equations

2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

Replacing x value in 2x+8y=420

∴ 2(120-y)+8y=420

∴ 240-2y+8y=420

∴ 6y=180

∴ y=30

Replacing y value in any equation

∴ x=120-y=120-30=90

∴ x=90

Thus,

Volume of Mixture A is x=90 ml

Volume of Mixture B is y=30 ml

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dangina [55]

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3 years ago