Answer:
What is the best memory you have?
(pls nothing inapropriate)
Explanation:
Answer:
A. y = 6x + 10
Explanation:
Tangent line is just the point-slope formula. So your goal is to find the slope and the point (x₀, y₀) to plug into the equation.
The slope could be found by plugging in the derivative.
The (x₀, y₀) could be found by plugging in the original equation.
fun one - thanx 4 posting!!!
let the interaction of BK and NO be P
and NO be x
triangle NBO n ABC are similar by AAA as NO // AC
so BP/BK=NO/AC=x/30
BP=10*x/30=x/3
PK=height of triangle NMO
cuz' NM=MO n m∠NMO=90°
height of triangle NMO=NO/2=x/2
PK=x/2
area of triangle NBO + area ot trapezoid NOCA = area of triangle ABC
BP*NO/2 + (NO+AC)*PK/2 = BK*AC/2
(x/3)*x/2+(x+30)*x/2 = 10*30/2
simplifying x^2/6+x^2/4+30x/4=150
5x^2+90x-1800=0
solving x=12 or x=-30
as length cannot be negative
NO=12