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nataly862011 [7]
3 years ago
12

Equation of the line tangent

Advanced Placement (AP)
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

A. y = 6x + 10

Explanation:

Tangent line is just the point-slope formula. So your goal is to find the slope and the point (x₀, y₀) to plug into the equation.

The slope could be found by plugging in the derivative.

The (x₀, y₀) could be found by plugging in the original equation.

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-6x+5y=8 2x-4y=2 i need a x,y answer and i need some steps too
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Answer:

I. x = -3

II. y = -2

Explanation:

Given the following algebraic equation;

-6x + 5y = 8 .........equation 1

2x - 4y = 2 ..........equation 2

We would solve the algebraic equation using the substitution method

From equation 1;

5y = 8 + 6x

y = \frac {8 + 6x}{5} .....equation 3

Substituting eqn 3 into eqn 2, we have;

2x - 4(\frac {8 + 6x}{5}) = 2

2x - \frac{32 + 24x}{5} = 2

Multiplying all through by 5

10x - 32 - 24x = 10

Rearranging the equation, we have:

10x - 24x = 10 + 32

-14x = 42

x = \frac {-42}{14}

x = -3

Next we find the value of y;

From eqn 3;

y = \frac {8 + 6x}{5}

Substituting the value of "x" into the equation, we have;

y = \frac {8 + 6*(-3)}{5}

y = \frac {8 - 18}{5}

y = \frac {-10}{5}

y = -2

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