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NikAS [45]
3 years ago
13

How many solutions can a single variable linear equation contain?

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0
One solution. Given that there is only one variable and it is linear, we know it must only have one solution. <span />
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-12,60,-300,1500 what are the next two numbers on the pattern
Rina8888 [55]

Answer:

The next two numbers are -7500 and 37500

Step-by-step explanation:

To find the pattern, divide any number by the previous.

-300/60 = -5.

Meaning they are being multiplied by -5, so we can just multiply this to the last number.

1500 * -5 = -7500,

-7500 * -5 = 37500.

3 0
3 years ago
PLZ HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!
notsponge [240]

Answer:

$72 would be the retail price

Step-by-step explanation:

6 0
3 years ago
Xavier needs to bike a minimum of 80 miles this week for his training. If he already biked 14 miles this week, then how many mil
ioda
Hi.

First, let's calculate how many miles he has left.

80 - 14 = 66

Now, to figure out how many miles a day in 6 days, divide.

66/6 = 11

Xavier should bike 11 miles on each of the 6 remaining days.
3 0
2 years ago
Which expression is equivalent to (+12)×5+7 ?
riadik2000 [5.3K]
B

(12)x5 + 7
\ /
12 + 12
3 0
2 years ago
In an experiment to determine whether there is a systematic difference between the weights obtained with two different mass bala
Maslowich

Answer:

H0: μd=0 Ha: μd≠0

t= 0.07607

On the basis of this we conclude that the mean weight differs between the two balances.

Step-by-step explanation:

The null and alternative hypotheses as

H0: μd=0 Ha: μd≠0

Significance level is set at ∝= 0.05

The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571

The test statistic under H0 is

t = d/ sd/ √n

Which has t distribution with n-1 degrees of freedom

Specimen        A               B           d = a - b         d²

1                     13.76        13.74         0.02           0.004

2                    12.47        12.45          0.02         0.004

3                    10.09        10.08           0.01        0.001

4                       8.91       8.92          -0.01          0.001

5                     13.57      13.54           0.03        0.009

<u>6                     12.74      12.75          -0.01        0.001</u>

<u>∑                                                      0.06         0.0173</u>

d`= ∑d/n= 0.006/6= 0.001

sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882

sd= 0.05368

t= 0.001/ 0.05368/ √6

t= 0.18629/2.449

t= 0.07607

Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.

3 0
3 years ago
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