Answer:
i think its $2
Step-by-step explanation:
because 1,2 could mean 1 bag = $2,
2,4 could mean 2 bags = $4, and so on.
Answer:
i'm not sure
Step-by-step explanation:
Answer:
p-q= -4
p=q-4
x^2 + px + q=0
=> x^2 + (q-4)x + q = 0
d= b^2-4ac
=(q-4)^2 - 4(1)(q)
= q^2 + 16 -8q - 4q
=q^2 -12q+16
given that D=16
q^2 -12q+16 = 16
=> q^2 -12q = 0
=> q^2 = 12q
=> q = 12q/q
=> q= 12
Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8
Hope you understood............
Answer: range= 26, variance= 80 and standard deviation= 8.94
Step-by-step explanation:
Range = highest - lowest
Range = 146 - 120
Range= 26
Let m be mean
M=mean=sum/n
Mean=(120+134+146+127+138+133) / 6
M=798/6
M=133
The standard deviation sample formula:
S.D = sqrt( Summation of |x-m|^2 / n-1)
Let start finding:
|x-m|^2
For 1st: |120-133|^2=169
For 2nd: |134-133|^2=1
For 3rd: |146-133|^2=169
For 4th: |127-133|^2=36
For 5th: |138-133|^2=25
For 6th: |133-133|^2=0
Summation of |x-m|^2 = 400
The standard deviation formula is :
S.D = sqrt( Summation of |x-m|^2 / n-1)
S.D= sqrt(400 / 5)
S.D=sqrt(80)
S.D= 8.94
Variance = (Summation of |x-m|^2 / n-1)
Variance= 400/5
Variance= 80
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
