For the problem are you supposed to be solving for x
The picture in the attached figure
step 1we know that
It is given that AD and BD are bisectors of ∠CAB and ∠CBA respectively.
Therefore,
x = ∠CAB/2 -----> equation 1
y = ∠CBA/2 -----> equation 2
step 2In triangle ABC,
∠CAB + ∠CBA + ∠ACB = 180° ----> [The sum of all three angles of a
triangle is 180°]
∠CAB + ∠CBA + 110° = 180°
∠CAB + ∠CBA = 180° - 110°
∠CAB + ∠CBA = 70° ------> divide by 2 both sides
∠CAB/2 + ∠CBA/2 = 70/2 -------> equation 3
substitute equation 1 and equation 2 in equation 3
x+y=35
hence
the answer isx+y =35°
⇒ x + y = 35° ...[From equation (1) and (2)]
length = 15
let the width = w then length = 2w - 3
Perimeter = 2(length + width)
= 2(2w - 3 + w) = 2( 3w - 3) = 6w - 6 = 48
hence 6w = 48 + 6 = 54 ⇒ w =
= 9
Thus length = 2w - 3 = (2× 9) - 3 = 18 - 3 = 15
Answer:
-11 and -7
Step-by-step explanation:
(3s^13)(9s^-5) is simply a matter of multiplication.
First, multiply the coefficients, or the numbers in front of the s. In this case, 3s x 9s = 27s.
When multiplying exponents, you simply add them, so the next step is 13-5 or 8. Therefore your answer is 27s^8