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coldgirl [10]
2 years ago
5

Find two integers whose sum is -18 and product is 77

Mathematics
2 answers:
dmitriy555 [2]2 years ago
8 0

Answer:

-11 and -7

Step-by-step explanation:

Anettt [7]2 years ago
3 0

Answer:

-11 and -7

Step-by-step explanation:

-11 + (-7) = -18

-11 x -7 = 77

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\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0


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