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Crank
3 years ago
6

Which is the last step in conducting a URL search?

Computers and Technology
1 answer:
dimulka [17.4K]3 years ago
3 0
The user's browser renders the html code as a visual web page
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8. Give regular expressions with alphabet {a, b} for
balandron [24]

Answer:

i think its C

Explanation:

6 0
1 year ago
I need help also this counts as my second giveaway and last for today
kifflom [539]

Answer:

I am pretty sure its the Visual card

8 0
2 years ago
Read 2 more answers
Yolanda lost her left foot during her military service, but she has been issued a prosthetic that enables her to walk normally,
Alex17521 [72]

Answer:

The correct answer to the following question will be "Artificial and superficial".

Explanation:

  • Prosthetic is just an automated means of replacing or restoring the missing component, where Yolanda has missing her foot and sometimes a prosthetic leg has indeed been released that helps her to walk or stand normally and superficially, but once it is thoroughly investigated you wouldn't have seen Yolanda using this tool.
  • And as such the specified situation seems to be an example of how innovation would be artificial as well as a superficial medium of human capacity expansion.
8 0
3 years ago
A nonpipelined system takes 300ns to process a task. The same task can be processed in a 5-segment pipeline with a clock cycle o
Vladimir79 [104]

Answer:

Pipelined architecture is 1.667 times more speedy than non pipelined architecture.

Explanation:

There are five stages to to complete an instruction to execute in pipeline architecture. as

Stage 1:  Instruction Fetch

Stage 2: Instruction Decode

Stage 3: Execute

Stage 4: Memory Access

Stage 5 : Write Back

The pipeline architecture processed instruction as given below. Each Stage take 1 clock cycle, which is represented as CC.

                Stage 1           Stage 2         Stage 3         Stage 4            Stage 5

I1:              1cc                  2cc                 3cc                4cc                   5cc

I2              2cc                 3cc                  4cc               5cc                   6cc

I3              3cc                  4cc                 5cc              6cc                    7cc

I4              4cc                 5cc                  6cc              7cc                    8cc

each four Instructions set takes 8 Clock Cycles.

I5              9cc                  10cc                11cc               12cc                 13cc

I6              10cc                 11cc                  12cc             13cc                 14cc

I7              11cc                  12cc                 13cc              14cc                 15cc

I8              12cc                 13cc                  14cc              15cc                16cc

.

.

.

I97:             193cc            194cc              195cc              196cc               197cc

I98             194cc             195cc             196cc               197cc               198cc

I99            195cc             196cc              197cc              198cc               199cc

I100         196cc                197cc             198cc            199cc                 200cc

<u>Pipelined architecture Time Calculation</u>

So in pipeline architecture 100 instructions takes 200 clock cycles to execute.

1 Clock Cycle time period is = 60ns.

200 Clock Cycle =  60ns * 200 = 12000 ns

<u>Non Pipelined architecture Time Calculation</u>

1 task Time period= 300ns

100 task time period = 100 * 300 =  30000 ns

The difference between pipelined and non pipelined architecture time period is = 30000 - 12000 = 18000 ns

<u>Speedup ratio</u>

<em>Speed up ratio= 30000/18000 =  1.667</em>

7 0
3 years ago
Suppose that the following elements are added in the specified order to an empty binary search tree: Kirk, Spock, Scotty, McCoy,
patriot [66]

Answer:

Pre-order: Kirk, Chekov, Khaaaan, Spock, Scotty, McCoy, Sulu, Uhuru

In-order: Chekov, Khaaaan, Kirk, McCoy, Scotty, Spock, Sulu, Uhuru

Post-order: Khaaaan, Chekov, McCoy, Scotty, Sulu, Uhuru, Spock, Kirk

Explanation:

The binary search tree is described in the diagram below.

The pre-order traversal of the binary tree gets the root, then the left node and right node. The in-order traversal picks the left node, the root node, and then the right node while the post-order traversal of the binary tree follows the left node, right node, and then the root node.

6 0
2 years ago
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