Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[10000];//array of ten thousand capacity.
int n=0,min=INT_MAX;//decalring n and min variables.
do{
cin>>a[n];
}while(a[n++]!=0); //using do while loop to take input.
for(int i=0;i<n-1;i++)//looping to n-2th index because 0 is at n-1th index.
{
if(a[i]<min)
{
min=a[i];
}
}
cout<<"The minimum element is "<<min<<endl;//printing the minimum.
return 0;
}
Input:-
5 2 6 78 32 31 21 6 45 2 1 0
Output:-
The minimum element is 1
Explanation:
I have created an array of capacity 10000.Taking input till 0 is entered. Now the 0 is at the n-1 th index so we have to consider elements upto n-2th elements.Using for loop to iterate upto n-2 th index and finding the minimum among those elements.
Answer:
The code is checking if a word in the word list matches a certain length and the first letter matches a certain letter... the for loop is what increments through the word list checking each word one by one for the specified conditions. If the word meets the conditions it is added to an array called filteredWordList.
Explanation: