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3 years ago

Original price of a soda: $800 tax 7% selling price: $

Mathematics

1 answer:

Kobotan [32]3 years ago

3 0

Answer:

$856

Step-by-step explanation:

Find 7% of $800 and then add it to $800

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3, -2, -7,... what is the common difference of this arithmetic sequence

worty [1.4K]

Answer: -5

Step-by-step explanation: The common difference is the same number we are adding each time to get from one term to the next.

In this sequence, we are adding -5 each time

so our common difference is -5.

7 0

2 years ago

Which equation represents an exponential function with an initial value of 500?

Georgia [21]

Answer: C

Step-by-step explanation:

8 0

2 years ago

Solve for z. z12≤3 z≥36 z≤36 z≥4 z≤4

erastova [34]

Answer:

Your answer is correct... it's no.3 ... but if you multiply a inequality by a negative value the inequality sign changes.. like if you habe greater than it'll be less than... Keep that in mind too

5 0

3 years ago

Read 2 more answers

Denise makes three times as many chocolate cupcakes as vanilla cupcakes. She also makes three dozen strawberry cupcakes. If Deni

slamgirl [31]

Answer:

6 dozens

Step-by-step explanation:

Vanilla, v = x

Chocolate, c = 3x

Strawberry, s = 3 dozens = 36

Total cupcakes = 132

Hence,

x + 3x + 36 = 132

4x = 96

x = 96 / 4

x = 24

Chocolate = 3 * 24 = 72

Dozens of chocolate = 72 /12 = 6 dozens

7 0

2 years ago

A local sorority sold hot dogs and bratwursts at the spring fling picnics. The first day they sold 8 dozen hot dogs and 13 dozen

kicyunya [14]

Answer:

1 hot dog costs $0.75

1 bratwurst costs $1.35

Step-by-step explanation:

Let x and y be the price per dozen of hot dogs and bratwursts respectively.

The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60

8x + 13y = 282.60

The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00

10x + 15y = 333

and we have the linear system

8x + 13y = 282.60

10x + 15y = 333

which can be written in matrix form as

$\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}282.60\\333\end{array}\right)$

The solution would be given by

$\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}\left(\begin{array}{c}282.60\\333\end{array}\right)$

We have

$\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)$

hence

$\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)\left(\begin{array}{c}282.60\\333\end{array}\right)=\left(\begin{array}{c}9\\ 16.2\end{array}\right)$

Now,

if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75

if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35

4 0

2 years ago