Answer: There are 32 pints of first type and 128 pints of second type in mixture.
Step-by-step explanation:
Since we have given that
Percentage of pure fruit juice in first type = 60%
Percentage of pure fruit juice in second type = 85%
Percentage of pure fruit juice in mixture = 80%
We will use "Mixture and Allegation" to find the ratio of first and second type in mixture:
First type Second type
60% 85%
80%
------------------------------------------------------------------------
85-80 : 80-60
5% : 20%
1 : 4
so, the ratio of first and second type is 1:4.
Total number of pints of mixture = 160
Number of pints of mixture of first type in mixture is given by
![\dfrac{1}{5}\times 160\\\\=32\ pints](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B5%7D%5Ctimes%20160%5C%5C%5C%5C%3D32%5C%20pints)
Number of pints of mixture of second type in mixture is given by
![\dfrac{4}{5}\times 160\\\\=4\times 32\\\\=128\ pints](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B5%7D%5Ctimes%20160%5C%5C%5C%5C%3D4%5Ctimes%2032%5C%5C%5C%5C%3D128%5C%20pints)
Hence, there are 32 pints of first type and 128 pints of second type in mixture.
Answer:
7200
Step-by-step explanation:
100/(100-15) * 6120 = 7200
Answer: Width of canvas = 9 inches
Area left for painting after painting the border = 70 square inches.
Explanation :
Since we have given that
Area of painting = 108 square inches
Length of canvas = 12 inches
As we know that
![\text{Area of rectangle} = length\times breadth](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20rectangle%7D%20%3D%20length%5Ctimes%20breadth)
![108=12\times breadth\\\\\frac{108}{12}=breadth\\\\9=breadth](https://tex.z-dn.net/?f=108%3D12%5Ctimes%20breadth%5C%5C%5C%5C%5Cfrac%7B108%7D%7B12%7D%3Dbreadth%5C%5C%5C%5C9%3Dbreadth)
So, breadth of canvas = 9 inches .
Now, Chloe paints a 1 inch wide blue border on the canvas.
![\text{So, remaining length left for painting after painting the border} = 9-1-1=9-2=7\text{ inches}](https://tex.z-dn.net/?f=%5Ctext%7BSo%2C%20remaining%20length%20left%20for%20painting%20after%20painting%20the%20border%7D%20%3D%209-1-1%3D9-2%3D7%5Ctext%7B%20inches%7D)
![\text{So , area of remaining portion }= length\times breadth \\\\ \text{ area of remaining portion }=7\times 10\\\\\text{ area of remaining portion }=70 \text{ square inches}](https://tex.z-dn.net/?f=%5Ctext%7BSo%20%2C%20area%20of%20remaining%20portion%20%7D%3D%20length%5Ctimes%20breadth%20%5C%5C%5C%5C%20%5Ctext%7B%20area%20of%20remaining%20portion%20%7D%3D7%5Ctimes%2010%5C%5C%5C%5C%5Ctext%7B%20area%20of%20remaining%20portion%20%7D%3D70%20%5Ctext%7B%20square%20inches%7D)
Hence, remaining area = 70 square inches .
Answer: 0.08 yards
Step-by-step explanation: 1 centimeter equals to about 0.01 yards. You have to multiple 0.01 to 8 and it will give 0.08 yards.
7^2 - 3(4-2)^0 - 2(7+3) + 3^2
= 49 - 3 - 20 + 9
= 35