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1 year ago

Which symbol makes the comparisons true ? Complete the comparison -6 ? 3

Mathematics

1 answer:

Usimov [2.4K]1 year ago

6 0

<h3>Hello!</h3>

$======================================$

Negative numbers are always less than positive ones.

Do you remember the symbol for "less than"? That's right, "<" :)

Hence,

-6<3

Because

-6 is negative (the - sign tells us that)

3 is positive

$===================================$

<h3>Notes:</h3>

Hope everything is clear.
Let me know if you have any questions!

<h3>Answered by:</h3>

~DiamondS~

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Find exact values for sin θ and tan θ if cos θ = -4/9 and tan θ > 0.

julsineya [31]

Answer:

Part 1) $sin(\theta)=-\frac{\sqrt{65}}{9}$

Part 2) $tan(\theta)=\frac{\sqrt{65}}{4}$

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find $sin(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$cos(\theta)=-\frac{4}{9}$

substitute

$sin^{2}(\theta) +(-\frac{4}{9})^{2}=1$

$sin^{2}(\theta) +\frac{16}{81}=1$

$sin^{2}(\theta)=1-\frac{16}{81}$

$sin^{2}(\theta)=\frac{65}{81}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{65}}{9}$

Remember that

In this problem the sine of angle theta is negative

$sin(\theta)=-\frac{\sqrt{65}}{9}$

step 2

Find $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{65}}{9}$

$cos(\theta)=-\frac{4}{9}$

substitute the given values

$tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}$

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3 years ago

There are a total of 225 pupils in Secondary one. If the number of pupils who pay their school fees through GIRO scheme is 14 ti

asambeis [7]

There are several information's already given in the question. Lat us first write them down and then go for solving the problem.

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Then
Number </span>of pupil who pay the school fees through GIRO scheme = 14x
So
x + 14x = 225
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3 years ago

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an=ar^(n-1)
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