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4 years ago

Please help me thnk you

Mathematics

2 answers:

kramer4 years ago

8 0

For this question, we use the Pythagorean theorem.

$a^2+b^2=c^2$

We know the lengths of the legs, a and b.
$a=3$
$b=4$

Now, let's solve for the hypotenuse, c.

$3^2+4^2=c^2$
$25=c^2$

Take the positive square root.

$\boxed{c=5}$

Hope this helps! :)

Usimov [2.4K]4 years ago

5 0

5 is the answer

this is the most common triangle a 3-4-5 right triangle

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Dominik [7]

Answer:

X=50

Step-by-step explanation:

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25×2=50

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3 years ago

A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

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$\angle SPR$ =Angle subtended by the statue to where you are standing.

$\angle x=\angle RPQ$ = which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ} =\frac{21}{57}$

Which gives $\angle x$ to be:

$\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ can be added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta SPQ$ .

We can again use the tan trigonometric ratio in $\Delta SPQ$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57tan(27.32^0)$

$h\approx8.45 ft$

Thus, the height of the statue is approximately, 8.45 feet.

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3 years ago

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Rina8888 [55]

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Answer:

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Step-by-step explanation:

It would be 29.41176 if you want the answer to be exact. All you're doing is dividing 10.00 ÷ 0.34 and getting 29 oranges :)

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