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bulgar [2K]
3 years ago
8

What method would best to solve x=5y. 2x-3y=7

Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

substituting x=5y into 2x-3y=7, Answer: y = 1 x = 5

Step-by-step explanation:

2(5y)-3y=7

10y-3y=7

7y=7

y=1

substitute y=1 into x=5y

x=5(1)

x=5


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Can someone please help me with this
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Answer:

3. How many faces do each of the following have?

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5 0
3 years ago
Choose the best coordinate system to find the volume of the portion of the solid sphere rho &lt;_4 that lies between the cones φ
MrRissso [65]

Answer:

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

Step-by-step explanation:

We get the limits of integration:

R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq  4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace

We use the spherical coordinates and  we calculate a triple integral:

V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4  \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}}  \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\

we get:

V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

4 0
3 years ago
Help me please asap
LiRa [457]

Answer:

x = 20

Step-by-step explanation:

AE is an angle bisector, which means it cuts that triangle into 2 equal halves. So this means ∠BAE and ∠EAC should be equal to each other.

Set them equal to each other and solve for x.

∠BAE = ∠EAC

x + 30 = 3x - 10

40 = 2x

x = 20

3 0
3 years ago
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