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2 years ago

I NEED HELP NOW PLS PLS THANK YOU PLS

Mathematics

2 answers:

liq [111]2 years ago

7 0

I think A.... I could be wrong tho

Murrr4er [49]2 years ago

4 0

Answer:

It's C

Step-by-step explanation:

It's C because when you find the least common denominator of 3 and 5 it's 15. So then you convert the fractions to get 6/15+5/15=11/15, which leaves 4/15 left.

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2/9 h = 8<br><br> h=<br><br> Pls tell me what h = !

Wewaii [24]

Answer:

h=36

.......................

3 0

3 years ago

Please help me !! ASAP!

Anettt [7]

Answer:

3√265

Step-by-step explanation:

The distance between the given points is √265. If all the side are the same length on an equilateral triangle, then the perimeter is 3 times as long.

3 0

2 years ago

There are 23 perfect tests taken.

Grace [21]

Answer:

92%

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Help. What’s the answer to this problem?

liq [111]

Answer:

C) Yes, it’s a reflection over line f.

Step-by-step explanation:

It’s a reflection over line f.

3 0

2 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

2 years ago