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sashaice [31]
3 years ago
5

PLEASE HELP!! surface area of composite figures..

Mathematics
2 answers:
STALIN [3.7K]3 years ago
5 0
Cut the shape into shapes you know the area of and do the formula this helps
bezimeni [28]3 years ago
5 0

Cut the shape into shapes you know the area of and do the formula this helps

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I NEED HELP ON A TEST HELP QUICK
Alisiya [41]
Boats are blue and red
6 0
3 years ago
Help pls!!!! And I will give pizza forever!!!
SOVA2 [1]
The number of red  beads are increasing by 2  for each new pattern
The next number of reds will be 12.  ( in patern 5)

number of blue beads in pattern 5 will be 15 ( increasing by 3 )

nth term for red  = 4 + 2 (n-1)  ( its an arithmetic sequence)

nth term for blue =  3 + 3(n - 1)   - as above ,arithmetic.

Total beads in pattern 45 is

No. red beads in pattern 26   = 4  + 2(26-1)  = 4 + 50 = 54
No  blue beads in pattern 60 =  3 + 3(59)  =  180

Total number of beads in pattern 45 is:-

 4 + 2(44) + 3 + 3(44)  =   227 


7 0
3 years ago
What is the Value of x in the equation 2.5x + 10 = x-0.5 ?
marshall27 [118]

Answer: 7

Step-by-step explanation:

2.5x+10=x-0.5\\2.5x-x+10=-0.5\\1.5x=-0.5-10\\1.5x=-10.5\\x=\frac{10.5}{1.5}\\ x=7

7 0
3 years ago
Read 2 more answers
Point S is on line segment \overline{RT}
Semenov [28]

Answer:

RT = 20

Step-by-step explanation:

Point S is on line segment

R------------S------------T

RS + ST = RT

Given

ST=3x-8

RT=4x

RS=4x-7,

Step 1

We find x

4x - 7 + 3x - 8 = 4x

4x + 3x -7 - 8 = 4x

7x - 15 = 4x

7x - 4x = 15

3x = 15

x = 15/3

x = 5

Step 2

We find RT

RT = 4x

x = 5

RT = 4 × 5

RT = 20

The numerical length of RT is 20

3 0
3 years ago
How do you solve this
AlladinOne [14]

Answer:

  • domain: all terms are defined for <em>all real numbers</em>
  • solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6

6 0
3 years ago
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