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kaheart [24]
3 years ago
9

Order these objects from heaviest to lightest. (Note: 1 pound = 16 ounces, 1 kilogram ≈ 2.2 pounds ,and 1 Tom = 2,000 pounds) it

em school bus weight 9 tons item horse 1,100 pounds elephant 5,500 kilograms grand piano 15,840 ounces
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

Ordering of objects from heaviest to lightest are  ⇒ <u> school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.</u>

Step-by-step explanation:

Given:

School bus weight = 9 tons.

Horse = 1,100 pounds.

Elephant = 5,500 kilograms.

Grand piano = 15,840 ounces.

Now, order these objects from heaviest to lightest.

So, we need to take a common unit to order the items:

Thus, we take pounds as a common unit.

16 ounces = 1 pound.

1 kilogram = 2.2 pounds.

1 ton = 2,000 pounds.

Then, we calculate the weight of all items in pounds:

School bus 9 tons  =9\times 2000=18000\ pounds.

Horse 1100 pounds  =1100\ pounds.

Elephant 5500 kilograms  =5500\times 2.2=12100\ pounds.

Grand piano 15840 ounces  =15840\div 16=990\ pounds

According to question:

Ordering from heaviest to lightest:

<em>School bus = 18000 pounds, elephant = 12100 pounds, horse = 1100 pounds and grand piano = 990 pounds.</em>

Therefore, ordering of objects from heaviest to lightest are  ⇒  school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.

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Answer:

When solving for x, answer = \large\boxed{x = 5a - 8}

When solving for a, answer = \large\boxed{a = 1/5x + 8/5}

Step-by-step explanation:

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Start by multiplying 6 by the values in the parenthesis

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Add 24 to both sides of the equation

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Subtract 48 from both sides of the equation

6x = 30a - 48

Divide both sides of the equation by 6

x = 5a - 8 (Answer when solving for x)

Add 8 to both sides of the equation

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Divide both sides of the equation by 5

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-----------------------------------------

When solving for x, answer = \large\boxed{x = 5a - 8}

When solving for a, answer = \large\boxed{a = 1/5x + 8/5}

Hope this helps :)

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Step-by-step explanation:

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A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
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No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
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One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
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