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IrinaK [193]
2 years ago
6

Work out an expression for the nth term for this sequence: 23,35,47,49

Mathematics
1 answer:
notsponge [240]2 years ago
7 0
<h3>Answer:</h3>

a_n = 23 +12(n -1)

<h3>Explanation:</h3>

The nth term of an arithmetic sequence is explicitly defined as a_n = a_1 +d(n -1) where a_1 is the first term of the sequence and d is the the common difference.

From the given first five terms of the sequence we can see that the first term is 23 so a_1 = 23.

The common difference, d, can be calculated by a_n - a_{n -1} so we'll find the common difference of the given sequence by letting n = 2

d = a_2 - a_{2 -1} \\d = a_2 -a_{1} \\d = 35 -23 \\ d = 12.

Now let's plug everything we know.

a_1 = 23

d = 12

a_n = 23 + 12(n -1)

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
Oksana_A [137]

Answer:

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

Step-by-step explanation:

Lets divide it in cases, then sum everything

Case (1): All 5 numbers are different

 In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.

The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.

{n \choose 5 } = \frac{n!}{5!(n-5)!}

Case (2): 4 numbers are different

We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4 {n \choose 4} .

We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.

The total cardinality of this case is 4 * {n \choose 4} .

Case (3): 3 numbers are different

As we did before, we pick 3 elements from a set of n. The amount of possibilities is {n \choose 3} .

Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have {3 \choose 2 } = 3  possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of 6 * {n \choose 3}

Case (4): 2 numbers are different

We pick 2 numbers from a set of n, with a total of {n \choose 2}  possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.

The total amount of possibilities for this case is

4 * {n \choose 2}

Case (5): All numbers are the same

This is easy, he have as many possibilities as numbers the set has. In other words, n

Conclussion

By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

I hope that works for you!

4 0
3 years ago
Solve for y 9x - y = -6x + 4y
Lyrx [107]

Answer:

y = 3x

Step-by-step explanation:

Given

9x - y = - 6x + 4y ( subtract 4y from both sides )

9x - 5y = - 6x ( subtract 9x from both sides )

- 5y = - 15x ( divide both sides by - 5 )

y = 3x

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3 years ago
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Answer:

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A student has a savings account earning 3% simple interest. She must pay $1200 for first-semester tuition by September 1 and $12
Bingel [31]

Using simple interest, it is found that she needs to earn $2,391.07 during the summer.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

  • A(0) is the initial amount.
  • r is the interest rate, as a decimal.

For this problem, the objective is to have <u>$1200 in 3 months = 0.25 years</u>, hence the parameters are given as follows:

A(0.25) = 1200, t = 0.25, r = 0.03.

Hence we have to solve for A(0):

A(0)(1 + 0.03 x 0.25) = 1200

A(0) = 1200/(1 + 0.03 x 0.25)

A(0) = $1,191.07.

She also needs to earn $1,200 to pay the first-semester bill on time, hence:

1200 + 1191.07 = $2,391.07.

She needs to earn $2,391.07 during the summer.

More can be learned about simple interest at brainly.com/question/16646150

#SPJ1

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