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UNO [17]
3 years ago
15

Please help me on this question

Mathematics
2 answers:
Vlad [161]3 years ago
3 0
About 5.3$ per pen. Brainliest?
KiRa [710]3 years ago
3 0
Hey CoolDog7757! To find the unit price you would have to divide the $4.75 by the 25 pens, which would equal $0.19. The unit price would be $0.19 per pen. Hope this helps! :)
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Jason has 5 shirts for every 2 pairs of pants. His brother John has 7 shirts for every 3 pairs of pants. Compare the ratio by co
postnew [5]

Answer:

john has a greater ratio of shirts to pants

Step-by-step explanation:

jason- 5:2

table:

shirt :5 10 15 20 25 30 35 40 45

pants:2 4   6   8   10 12  14 16 18 20

john-7:3

table:

shirts:7 14 21 28 35 42 49 56 63

pants:3  6 9 1 2  15  18  21 24  27

4 0
2 years ago
Evaluate:<br><br> -7 - (-8) + (-3) + 6 - 2<br><br> A) -2 <br> B) 0 <br> C) 1 <br> D) 2
Gala2k [10]

Answer:

D) 2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Choose the equation below that represents the line passing through the point -3, -1 with a slope of 4
andre [41]

Answer:

Y=4x-5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
3 years ago
I just need help explaining it. solve the system of equation
Maksim231197 [3]

SOLUTION

Write out the equation

\begin{gathered} y=\frac{1}{3}x-3 \\ 5x-3y=-3 \end{gathered}

To solve this system of equation, the aprropriate method will be substitution

Substitute the expression for y into the second equation for y, we have

5x-3(\frac{1}{3}x-3)=-3

Expand the paranthesis we have

\begin{gathered} 5x-x+9=-3 \\ \text{Simplify},\text{ by subtracting 9 from both sides } \\ 4x+9-9=-3-9 \\ 4x=-12 \end{gathered}

Divide both sides by 4, we have

\begin{gathered} \frac{4x}{4}=-\frac{12}{4} \\ \text{Then} \\ x=-3 \end{gathered}

Since the value of x has been obtained, we substitute into the first equation

\begin{gathered} y=\frac{1}{3}x-3 \\ \text{ recall x=}-3 \\ y=\frac{1}{3}(-3)-3 \\ y=-1-4 \\ \text{Hence } \\ y=-4 \end{gathered}

Therefore

x = -3, y= -4

6 0
1 year ago
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