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matrenka [14]
3 years ago
10

A plumber is fitting pipes for a remodeled kitchen sink. The sink requires 3 different sections of pipe; the first is 6√96 feet

long, the second section is 12√150 feet long, and the third section is 2√294 feet long. How many feet of piping is required for all 3 sections?
Mathematics
1 answer:
padilas [110]3 years ago
7 0
98 √6 feet is required for all 3 sections.

6 √96 + 12 √150 + 2 √294  = 0

Simplify each radical to be the same.

   6 √96  =   6 √16 * 6 =   6 * 4 √6 = 24 √6
12 √150 = 12 √25 * 6 = 12 * 5 √6 = 60 √6 
  2 √294 =   2 √49 * 6 =   2 * 7 √6 = 14 √6

Add the radicals.

24 √6 + 60 √6 + 14 √6 = 98 √6 feet
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Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =
marta [7]

Answer:

The integral for the arc of length is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

By using Simpon’s rule we get: 1.5355453

And using technology we get:  2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx

We need the derivative of the function:

f'(x)=\frac{1}{x}

And we need it squared:

[f'(x)]^2=\frac{1}{x^2}

Then the integral is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

Now, the Simposn’s rule with n=4 is:

\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)

In this problem:

a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}

So, the Simposn’s rule formula becomes:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then simplifying a bit:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then we just do those computations and we finally get the approximation via Simposn's rule:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%

8 0
3 years ago
total amount = P (1 + i)t What is the total amount that First Consumer Bank will receive after lending Jane $7,000 for three yea
ICE Princess25 [194]
P= principal (initial deposit) ($7000)
i= interest (5%)
t= # of years (3)

Total amount = P (1 + i)^t
T= $7000(1 + 5%)^3
T= 7000(1.05)^3
multiply exponents before regular multiplication
T= 7000(1.157625)
Total= $8,103.38 after 3 years

Hope this helps! :)
6 0
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