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vova2212 [387]
3 years ago
11

2. Identify the variables that are contained in the expression. 2m2 + 3mn + 4p

Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0

Answer:

m, n and p

Step-by-step explanation:

Given

2m^2 + 3mn + 4p

Required

List out the variables

Literally, the variables are the alphabets in the expression

And they are:

m, n and p

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-1+-1=-2

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A rectangular prism with a square base has height 12 ft. The volume of the prism is 3468 cubic feet. Determine the side length o
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PLEASE HELP ME WILL GIVE BRAINLIEST TO CORRECT ANSWER
alex41 [277]

common difference, d = -3

f1 = -13

An arithmetic sequence f(n) = f1 + d(n - 1)

so f(n) = -13 - 3(n - 1)

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Margarita [4]
<span>Angle T = Angle C, let them equal x

So x + x + 140 = 180

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6 0
4 years ago
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
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