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2 years ago

2. Identify the variables that are contained in the expression. 2m2 + 3mn + 4p

Mathematics

1 answer:

Alexeev081 [22]2 years ago

7 0

Answer:

m, n and p

Step-by-step explanation:

Given

$2m^2 + 3mn + 4p$

Required

List out the variables

Literally, the variables are the alphabets in the expression

And they are:

m, n and p

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Find the area of the rhombus. d1 = 14 m; d2 = 18 m The area of the rhombus is ? m2.

xxTIMURxx [149]

Answer:

Area of rhombus = 126 m²

Explanation:

We are given that the two diagonals of the rhombus are:

D₁ = 14 meters and D₂ = 18 meters

The area of the rhombus using its diagonals can be calculated using the following rule:

$Area = \frac{D_1 * D_2}{2}$

Substitute with the given values to get the area as follows:

$Area = \frac{14*18}{2}=126 m^2$

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Answer:

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2 years ago

Given that T is the centroid of △DEF and FT=12

dlinn [17]

The centroid of a triangle divides the median of the triangle into 1 : 2

The measure of FQ is 18, while the measure of TQ is 6

Because point T is the centroid, then we have the following ratio

$\mathbf{TQ : FT =1 : 2}$

Where FT = 12.

Substitute 12 for FT in the above ratio

$\mathbf{TQ : 12 =1 : 2}$

Express as fraction

$\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}$

Multiply both sides by 12

$\mathbf{TQ =\frac{1 }{ 2} \times 12}$

This gives

$\mathbf{TQ =\frac{1 2}{ 2}}$

Divide 12 by 2

$\mathbf{TQ =6}$

The measure of FQ is calculated using:

$\mathbf{FQ = FT + TQ}$

Substitute 12 for FT, and 6 for TQ

$\mathbf{FQ = 12 + 6}$

Add 12 and 6

$\mathbf{FQ = 18}$

Hence, the measure of FQ is 18, while the measure of TQ is 6