Explanation:
Let the size of a large server be L, and
the size of a small server be S.
We are given two scenarios,
2L+4S = 64.............(1)
and
L+3S = 40...............(2)
We solve the equations as follows
2(2)-(1)
2L-2L +6S-4S = 2*40-64
2S = 16
so S=8 ..................(3), size of small server
substitute (3) in (2)
L+3(8) =40
L = 40-24 = 16..............size of large server
Answer:
In a series connection, the current is the same through each component regardless of any kind of components are used or their values. The voltage drops across each component in the circuit are dependent upon the values of the components used in the circuit. Another way to view a series connection is that the positive end of each component is connected to the negative end of the previous component in a 'one after the other' arrangement. The negative end of each component is also connected to the positive end of the next component.
It is one of which every component is arranged in a series connection. Hence series circuit will have same current at all points of the circuit. The voltage drop across each component in the circuit adds up to sum of voltage source across each component and of an equivalent component value. Breaking of the series circuit will make entire circuit to stop working. Suppose consider the three bulbs are connected in series connection and if even one bulb burns out or broken then all the three bulbs will stop working as well. In series circuit components like current (I) is sum of all the element and Voltage is sum of all the voltage drops and resistance is the sum of individual resistances.
Explanation:
Answer:
usable capacity = 10 GB
Number of cylinders = 256
Block size = 4 KB
(1)Bytes in each cylinder = (10*230)/(256) = (10*222) = 40 MegaBytes
(2)Number of Blocks in each cylinder = (10*222)/(212) = 10K
(3)capacity of one track = 40 MegaBytes/(10*2) = 2 MB
Rotation speed = 3840 RPM
Number of rotations per second = 3840/60 = 64
Transfer rate = (2*64) = 128 MB/sec
Explanation:
Answer:

Explanation:
In order to obtain the decimal number we have to use the next formula:

(The position to the right of the decimal point we will take it as negative)
Using the formula we have:

