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PilotLPTM [1.2K]
4 years ago
6

Late nite lab pH indicator

Chemistry
1 answer:
olasank [31]4 years ago
5 0
Litmus paper maybe?  There are a bunch of things you can use for this, but high school chem teachers love their litmus paper
You might be interested in
Copper(II) sulfate forms a bright blue hydrate with the formula CuSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high eno
Arada [10]

Answer:

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

Explanation:

CuSO_4.nH_2O\rightarrow CuSO_4+nH_2O

Mass of hydrate of copper sulfate = 14.220 g

Moles of hydrate of copper sulfate =\frac{14.220 g}{(159.5+n\times 18) g/mol}

Mass of copper sulfate after heating = 8.9935 g

Moles of copper sulfate = \frac{8.9935 g}{159.5 g/mol}

\frac{14.220 g}{(159.5+n\times 18) g/mol}=\frac{8.9935 g}{159.5 g/mol}

Solving for n, we get:

n = 5

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

5 0
3 years ago
1. What is the name for rise of deeper water to the surface?
Vikentia [17]

Upwelling

Explanation:

The rise of deeper water to the surface is called upwelling.

Upwelling is a term used in oceanography to describe the rise of cold and denser water to the surface.

  • This occurs usually along the short where wave action is very prevalent.
  • Surface wave pushes away warm water.
  • Then deeper nutrient-rich cold water rises due to low density and volume of water on top.
  • This nutrient rich water supports biological activities because they are rich.
  • Wind along the coast can also force surface water down.

learn more:

Ocean density brainly.com/question/6760255

#learnwithBrainly

3 0
3 years ago
Oak tree
Murljashka [212]
Oak tree, because it’s the primary producer
3 0
3 years ago
Read 2 more answers
How many particles are in 5.00 grams of nitric acid?
Leto [7]

Answer:

0.0500

Explanation:

7 0
3 years ago
Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
Alborosie

<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

Ans: Ka for HNO3 = 1.23

6 0
3 years ago
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