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garik1379 [7]
3 years ago
5

Look at the table of SRP values below.

Chemistry
1 answer:
son4ous [18]3 years ago
3 0
In this case we only care about the copper and the hydrogen half reactions listed in the table. Both reactions are written as reduction reactions (gaining electrons) and the SRP (standard reduction potential) is listed on the right. In this case, copper ions have a higher reduction potential (+0.34V) in comparison to hydrogen (0.00V) so the copper ion reduction reaction in the table will be favoured in the cell.

In redox voltaic cells, oxidation (losing electrons) occurs at the ANODE, and reduction (gain electrons) occurs at the CATHODE.

To work out the final reaction, we reverse the unfavourable reduction half reaction so it becomes an oxidation reaction to produce a redox reaction, and we leave the favourable reduction half reaction as it is. So in this case, copper ions will be reduced to elemental copper at the CATHODE, and hydrogen(g) will be oxidised to hydrogen ions at the ANODE. Answer (D).

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11. if the ph of a solution increases from 2.0 to 4.0, the h3o^ ion concentration o a decreases by a factor of 2. b. decreases b
Wittaler [7]

Option (B) is the right answer.

Hydronium ion (H_{3}O^{+}) concentration decreases by the <u>factor of 100</u>, if the pH of a solution increases from 2.0 to 4.0.

<h3>What is pH?</h3>

The hydrogen ion concentration in water is expressed by pH. Specific to aqueous solutions, pH is the <u>negative logarithm</u> of the hydrogen ion (H+) concentration (mol/L) : pH = -log_{10}[H_{3}O^{+}  ]

Acidic solutions are those with a pH under 7, and basic solutions are those with a pH over 7. At this temperature, solutions with a pH of 7 are neutral (e.g.<u> pure water</u>). The pH neutrality <u>relies on temperature, falling below 7 if the temperature rises above 25 °C</u>.

<h3>Given: </h3>

pH1( initial pH) = 2.0

pH2( initial pH) = 4.0

[H3O+] =  initial hydronium concentration

[H3O+]* = final hydronium concentration

<h3>Formula used : </h3>

pH = -log_{10}[H_{3}O^{+}]

<h3>Solution: </h3>

pH = - log_{10}[H_{3}O^{+}] \\\\= > 10^{-pH} = [H_{3}O^{+}] \\\\similarly, \\\\10^{-pH} = [H_{3}O^{+}]*\\\\ = > 10^{-4} = [H_{3}O^{+}]*\\\\Now, \frac{[H_{3}O^{+}]*}{[H_{3}O^{+}]}  = 10^{-2}

Thus , the concentration of hydronium ion decreases by 100.

To learn more about pH :

brainly.com/question/15289741

#SPJ4

8 0
2 years ago
calculate the standard potential arising from the reaction in which NADH is oxidized to NAD and the corresponding biological sta
melisa1 [442]

Answer:

-219.99kJ

Explanation:

The acronym '' NADH'' simply stands for what is known as coenzyme 1 with full meaning of Nicotinamide Adenine Dinucleotide Hydride. This substance is useful in the production of energy. The oxidation reaction of NADH causes it to produce NADP⁺ and the oxygen produces water when it is in the reduction process. The balanced equation for the oxidation reaction is given below as:

NADPH ---------------------------------------------------------------------> NADP⁺H⁺ + 2e⁻.

Also, the balanced equation for the reduction reaction is given below as:

\frac{1}{2} O₂ + 2H⁺ + 2e⁻ --------------------------------------------------------------> H₂O.

It can be shown from the above REDOX reaction that the total number of electrons getting transferred is 2.

The  Gibbs energy = -nFE. where n = 2, F = faraday's constant = 96485.3329 C and E = overall cell potential.

The overall cell potential = E[ reduction reaction] - E[oxidation reaction] = 0.82 - (- 0.32 ) = 1.14 V.

Hence, the Gibbs energy = - 2 × 96485.3329 × 1.14 = -219.99kJ

7 0
3 years ago
At what temperature celsius will 19.4g of molecular oxygen, o2, exert a pressure of 1820mm hg in a 5.12th cylinder?
Jlenok [28]
Answer:
             T  =  -28.2 °C

Solution:

Data Given;
                   P  =  1820 mmHg  =  2.39 atm

                   V  =  5.12 L

                   m  =  19.4 g

                   R  =  0.0821 atm.L.mol⁻¹.K⁻¹

Calculating moles,

                             n  = 19.4 g ÷ 32 g.mol⁻¹

                             n  =  0.606 mol

Assuming that the oxygen gas is acting perfectly, then according to Ideal Gas Equation,
                                P V  =  n R T

Solving for T,
                                T  =  P V / n R

Putting values,

              T  =  (2.39 atm × 5.12 L) ÷ (0.606 mol × 0.0821 atm.L.mol⁻¹.K⁻¹)

              T  =  244.7 K
Or,
              T  =  -28.2 °C
6 0
3 years ago
Read 2 more answers
Zinc metal reacts with hydrochloric acid (HCl) to produce hydrogen gas. What best describes this reaction?
Lena [83]

Answer: What best describes the reaction is "A single replacement reaction takes place because zinc is more reactive than hydrogen."

8 0
3 years ago
Copper has a density of 8.96 g/cm3 . if a cylinder of copper weighing 48.85 g is dropped into a graduated cylinder containing 20
Ronch [10]

To solve for the new water level, let us first calculate for the volume of the copper cylinder. The formula we can use is:

V = m / ρ

where V is the volume, m is the mass of the copper and ρ is the density, therefore:

V = 48.85 g / (8.96 g / cm^3)

V = 5.45 cm^3

since cm^3 = mL

V = 5.45 mL

 

The new water level will be the initial volume of the graduated cylinder plus the volume of the copper cylinder, therefore:

new water level = 20 mL + 5.45 mL

new water level = 25.45 mL

5 0
3 years ago
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