Answer:
Because they are different oxides.
Explanation:
In both processes they are involve Iron Oxides, but in the case of Ellingham diagrams, it is consider the Iron in combination with oxygen to form FeO, so the melting point is around 1600 ºC. In the case of blast furnace, the Fe that is present in the ores, are primary the hematite (Fe2O3) and the magnetite (Fe3O4).
Answer:
The answer is (e) : phosphoglucomutase, UDP-glucose pyrophosphorylase, glycogen synthase then amylo-(1,4-1,6)-transglycosylase.
Explanation:
Phosphoglucomutase: Convert glucose-6-phosphate to glucose-1-phosphate.
UDP-glucose pyrophosphorylase: Form UDP-glucose from glucose-1-phosphate.
Glycogen synthase: Add the new glucose from UDP-glucose to the growing glycogen chain.
Amylo-(1,4-1,6)-transglycosylase: This is a branching enzyme, it initiates formation of branches evolving from the main chain.
Our bone marrow continuously makes new red and white blood cells. The lymphatic system consists of the bone marrow, the spleen, the thymus (in young people), and lymph nodes.
The empirical formula of the given compound is 
.
The correct option is B.
<h3>What is an empirical formula?</h3>
The empirical formula of a chemical compound is the simplest whole-number ratio of atoms contained in the substance.
Given,
1.0 g of S
1.5 g of O
To calculate the empirical formula, we will divide the masses of the elements by their atomic weight.
For sulfur
For oxygen
Now, divide the greater value of mole came by the smaller value
Thus, the empirical formula for the given compound is 1 for S and 3 for O
Learn more about empirical formula, here:
brainly.com/question/11588623
<span>Propane is C3H8
The balanced equation is:
C3H8 + 5 O2 --> 3 CO2 + 4 H2O
From the balanced equation you can see that for each mole of C3H8 you obtain 4 moles of H2O.
moles H2O = 5.0 moles C3H8(4 moles H2O/1 mole C3H8) = 20 moles H2O formed
Use Avogadro's number to find the number of molecules.
molecules H2O = 20 moles H2O(6.02 x 10^23 molecules/1 mole) = 1.20 x 10^25 H2O molecules</span><span>
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