Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
Answer:
D
Explanation:
I may be wrong but I think it's D
I cannot found the images of the microscopy anywhere. But I can explain how you can differentiate a procaryote from a eucaryote under a microscope.
The first difference between them is the size of the cell. eucaryotes are generally much bigger than procaryotes. Procaryotes are visible only at x100 objective, but eucaryotes are visible starting from the x10 zoom.
The second difference is the presence of a nucleus in eukaryotes and the absence of it in procaryotes.
The third difference is the presence of organelles in eukaryotes and the presence of a cell wall in procaryotes (only visible at electronic microscopy).
The correct answer is B. Peer review
