Answer:
125/6(In(x-25)) - 5/6(In(x+5))+C
Step-by-step explanation:
∫x2/x1−20x2−125dx
Should be
∫x²/(x²−20x−125)dx
First of all let's factorize the denominator.
x²−20x−125= x²+5x-25x-125
x²−20x−125= x(x+5) -25(x+5)
x²−20x−125= (x-25)(x+5)
∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx
x²/(x²−20x−125) =x²/((x-25)(x+5))
x²/((x-25)(x+5))= a/(x-25) +b/(x+5)
x²/= a(x+5) + b(x-25)
Let x=25
625 = a30
a= 625/30
a= 125/6
Let x= -5
25 = -30b
b= 25/-30
b= -5/6
x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)
∫x²/(x²−20x−125)dx
=∫125/6(x-25) -∫5/6(x+5) Dx
= 125/6(In(x-25)) - 5/6(In(x+5))+C
Answer:
a little bit of a function of the cabinet and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and the cockroaches and zig and sharko and oggy and
Answer:3
Step-by-step explanation:
A. 2^4(4n) = 2^48
2^16n = 2^48
16n = 48
n = 3
Answer:
Step-by-step explanation:
By AA Similarity, triangles ASR and EST are similar.
The ratio of the lengths of the sides of triangle ASR to those of EST is 6/8 or 3/4.
Also,
By a rule of proportions, you get
