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3 years ago

HELP!

Mathematics

2 answers:

topjm [15]3 years ago

5 0

Obtuse hope this is ok :)

Levart [38]3 years ago

5 0

Answer: This is a Obtuse angle

B.)Obtuse Angle

Step-by-step explanation:

The obtuse angle is the smaller angle. It is more than 90° and less than 180°. The smaller angle is an Obtuse Angle, but the larger angle is a Reflex Angle.

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What is the measure of c?<br> A. 20<br> B. 14<br> C. 16<br> D. 22

Harman [31]

Answer:

Step-by-step explanation:

The measurements of the segments fall on similar triangles. This means the lengths of each segment can be found using proportions.

Remember, a proportion is an equation which sets equal ratios equal to each other.

$\frac{c}{k}=\frac{a}{j}\\\\\frac{c}{32}= \frac{15}{24}$

To solve for c, multiply numerators and denominators across the equal sign:

24c = 32(15)

24c = 480

c = 20

5 0

3 years ago

Please answer soon!!!

nalin [4]

C hope it helps you

8 0

3 years ago

Which of the following is not a factor of the polynomial function shown in the graph? 100 points!

atroni [7]

Answer:

Step-by-step explanation:

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3 years ago

What is the correct solution to the equation? 5(x - 5) = 15

Sloan [31]

C. 8

You substitute 8 into x, which makes the equation 5(8-5) = 15. 8-5 is 3, and 5 x 3 = 15.

7 0

4 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago