Let x= measure of angle 1
Let y= measure of angle 2
This is solving a system of equations
3x=30+ 5y which can also be written
3x-5y=30, and
2x+2y=180
There are a few ways to solve this, like solving for x in one of the equations and plugging it in for x in the other equation, but here is another way:
2(3x-5y)=2*30
3(2x+2y)= 3*180
6x-10y=60
6x+6y=540, and now subtract to get rid of x
0-16y=-480
Y=30
Plug it back in to either equation and you get x=60
10x+2y=18
10x-7y=-18
Multiply the second one by -1
-10x+7y=18
Then add the two equations
10x+2y=18
+-10x+7y=18
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9y=36
y=4
Plug that back into one of the equations above and solve for x
10x+2y=18
10x+2(4)=18
10x+8=18
10x=10
x=1
so your answer is x=1 and y=4 or (1,4)
Answer:
cross multiply
Step-by-step explanation:
Answer:
28
Step-by-step explanation:
