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viva [34]
3 years ago
10

Please help! Thank you!

Mathematics
2 answers:
Lena [83]3 years ago
4 0
103. Does not represent a function and 104. Does represent a funtion
rosijanka [135]3 years ago
4 0
*103 does not represent a function. You can check this by drawing a straight line down the graph, if the line touches more than one point it is not a function.

*104 does represent a function since the "line" would only touch one point in the graph.

Hope this helped
:D
You might be interested in
What is the measure ​
nekit [7.7K]

Answer:

b = 12

Step-by-step explanation:

Complementary angles add to 90 degrees

a+b = 90

78+b = 90

Subtract 78 from each side

78-78+b = 90-78

b = 12

5 0
3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
Which is the best option?
rusak2 [61]

Answer:

A would have to be the best answered all the all ones dont seen right

6 0
2 years ago
Use the rules of exponents to evaluate or simplify. Write without negative exponents. 1/4^-1/2 = ___ a0
Nastasia [14]

For this case we have, by definition:


a^{-b} =\frac{1}{a ^ b}

So, we have:


\frac{1}{4}^{-\frac{1}{2}}=\frac{1}{(\frac{1}{4})^{\frac{1}{2}}}

On the other hand we have that by definition:


a^{\frac{1}{2}}=\sqrt{a}

Thus, the expression can be written as:


\frac{1}{\sqrt {\frac{1}{4}}} =

\frac{1}{\frac{1}{\sqrt{4}}}

\frac{1}{\frac{1}{2}}

\frac{1*2}{1*1}=2

So, we have:


\frac{1}{4}^{-\frac{1}{2}}= 2

Answer:


\frac{1}{4}^{-\frac{1}{2}}= 2


4 0
3 years ago
Please help with the equation
Anastaziya [24]

Answer:

The distance is dependent

Step-by-step explanation:

Time is always the dependent variable because time will always stay the same when other things change, such as distance.

3 0
3 years ago
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