Answer:
b
Step-by-step explanation:
Answer:
Step-by-step explanation:
y - 9 = 3(x - 0)
y - 9 = 3x - 0
y = 3x + 9
Answer:
$36
Step-by-step explanation:
Jim worked from 8am - 2 pm , which is 6 hours
Woody worked form 10am - 2pm, which is 4 hours
If we take the total time (4+6 = 10) and divide the amount they got, we have:
$60/10 = $6 per hour worked
Since Jim worked 6 hours, he will be paid 6 * 6 = $36
The rest, 60 - 36 = $24 would be paid to Woody (he worked less).
Jim's fair share of earning is $36
Answer: b=0
Step-by-step explanation:
0.5b+4=2(b+2)
0.5b+4=2b+4
4=1.5b+4
0=1.5b
b=0
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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