The final velocity of the bock over the given distance is 12m/s.
Acceleration of the block
The acceleration of the block is calculated as follows;
F = ma
a = F/m
a = 40/10
a = 4 m/s²
hope this helps <3
Answer:
u problem can not be fixed, sorry
Answer:
32°
Explanation:
From the question, we are told that:
The measure ∠BQS of is 80°.
In the above diagram, m∠BQN = 48°
What is the m∠NQS?
∠BQS = m∠BQN + m∠NQS
80° = 48° + m∠NQS
m∠NQS = 80° - 48°
m∠NQS = 32°
Therefore, m∠NQS = 32°
When a body is moving in circular path at a
distance r from its center its velocity at any
instant will be directed tangentially. This is
what we call tangential velocity. It is
calculated as follows:
Vt=r(w)
where w = 5 rev/s (2m rad / rev) = 31.42
rad/s
Vt = 0.24(31.42) = 7.5 m/s
