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Y_Kistochka [10]
3 years ago
6

A Koch snowflake begins with an equilateral triangle with side length of 1 (stage 0). Trisect each side and attach a smaller equ

ilateral triangle to the center of each side (stage 1). Repeat for each triangle to obtain stage 2. Find the perimeter of the stage 2 snowflake.
Mathematics
1 answer:
nata0808 [166]3 years ago
7 0
Each triangle will have a side length of 1/3.
Since you do this for the 3 sides, each equilateral triangle has a perimeter of 1, so the 3 triangles will have a total perimeter of the stage 2 snowflake = 3
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