I think 20×5=100 then 100÷2
First put a bubble around 5x-7. Now you plug that into the problem. -3x-2
(5x-7)=12. now times the -2 by 5x which is -10x. and then times the -2 by -7 which is 14. so now you have -3x-10x+14=-12. add the -3x and -10x. -13x. Add the 14 over. -13x=2. Now dived by -13, which gives us x=-0.15
Now you take that a plug it into the -3x-2y=-12. So that it looks like this -3(-0.15)-2y=-12
Now times the -3 by -0.15 to give us 20 -2y=-12. Now 'kill' the 20, so that it looks like this -2y=-32. Now you divide by -2 and get y=16.
Now your ordered pair is (-0.15,16)
If the discriminant of a quadratic equation, given by B^2-4AC is positive, it has 2 real solutions. If 0, it has 1 real solution and if negative it has 0 real solutions.
The answer is
96%.
Explanation:
It is generally presumed that the scores are normally distributed.
1) You are given how many standard deviations from the mean Jeremy's score is. This is exactly the definition of the
z-score. Therefore z = 1.75
2) Look at a left-tail z-table in order to find the area of the normal curve on the left of your z-score (see picture attached). A = 0.9599
3) Multiply the area by 100 in order to find the
percentile:
<span>0.9599 </span>× 100 = 95.99
Therefore, 95.99% of the students scored less than Jeremy.
Hence, the answer is
96%.