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mixas84 [53]
4 years ago
12

Determine the horizontal asymptote ..

Mathematics
1 answer:
inessss [21]4 years ago
3 0
If we do the division  we get x^2 + 3/x-2
there will be an a vertical asymptote at x = 2  but no horizontal asymptote
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Can you help me in that problem​
nataly862011 [7]

Answer:

(x - 10, y - 13)

Step-by-step explanation:

We have two shapes on a graph and the question is asking for the translation of rhombus QRST to rhombus Q'R'S'T.

Looking at the graph we can see that not only does the rhombus move backwards, but also downward, this indicates that our answers will be in a subtracting symbol.

So all we have to do is count the amount of spaces rhombus QRST went to get to rhombus Q'R'S'T

3 0
3 years ago
Given this table of values, what is the value of f(14)?
Vikentia [17]

Answer:

f(14) = 14.6

Step-by-step explanation:

Form the table attached,

Values of 'x' represent the points on the x-axis of the graph of the given function 'f'.

Similarly, values of 'y' represent the points on the y-axis of the graph.

For every input value of x we get an output value 'y'.

f(10) = -12

f(-16) = 15.6

f(14) = 14.6

f(-18) = 14

Therefore, from the given table output value of f(14) will be 14.6

5 0
3 years ago
3 3/5 + 1 1/6 answer as a fraction
Diano4ka-milaya [45]

Answer:

  • \boxed{\sf{4\dfrac{23}{30} }}

Step-by-step explanation:

It is necessary to add the whole numbers of fractions from left to right in order to solve this problem.

<h3>3 3/5+1 1/6</h3>

<u>First, you have to add the whole numbers.</u>

3+1=4

<u>After that, you can combine by a fraction.</u>

6*3=18

18/5+ 1 1/6

1+6=7

7/6

<u>Rewrite the problem down.</u>

18/5+7/6

<u>Solve.</u>

5*6=30

143/30

=23/30

\boxed{\sf{4\dfrac{23}{30} }}

  • <u>Therefore, the final answer is 4 23/30.</u>
<h3 />

I hope this helps you! Let me know if my answer is wrong or not.

5 0
3 years ago
I need help with how to graph
dsp73
How can I help u tell me
7 0
3 years ago
Solve the equations below exactly. Give your answers in radians, and find all
kotegsom [21]

Answer:

See below (along with unit circle attached)

Step-by-step explanation:

sin(t)=-\frac{\sqrt{3}}{2}

t=\frac{4\pi}{3},\frac{5\pi}{3}

cos(t)=\frac{1}{2}

t=\frac{\pi}{3},\frac{5\pi}{3}

It really helps to use the unit circle! I've attached it below for your convenience. Keep in mind that a point on the unit circle is defined by (cos(\theta),sin(\theta)) where \theta is measured in radians.

8 0
2 years ago
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