X= 5x Y=-6 I just added them together
Let
The origin of coordinates the tree
r1 = vector position of the child 1.
r2 = vector position of the child 2
Child 1:
r1 = (12i + 12j)
Child 2:
r2 = (-18i + 11j)
The scalar product will be given by:
r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
The scalar product of their net displacements from the tree is -84m ^ 2
Equation of the line in slope intercept form is
y = 1/4 * x + 5. Slope is 1/4. Intercept is 5.
If x= 4, y = (1/4)*4 + 5 = 6.
The point (4,6) lies on the line.
Equation of the line in point slope form is
(y - y1)= m * (x - x1) where m is slope & (x1,y1) is point on the line.
Substituting slope m= 1/4 & point (4,6),
Equation of the line in point-slope form is:
(y - 6) = 1/4 * (x - 4).
Sanjay C.
(0,-1)(1,4)
slope = (4 - (-1) / (1 - 0) = (4 + 1)/1 = 5
y = mx + b
slope(m) = 5
(1,4)...x = 1 and y = 4
now we sub
4 = 5(1) + b
4 = 5 + b
4 - 5 = b
-1 = b
equation is : y = 5x - 1...answer C
Answer:
x=11
Step-by-step explanation:
M is the midpoint this means that we can set AM and BM equal to eachother, once this is done we can solve for x
9x-6=6x+27 (set equal to eachother)
9x=6x+33 (add 6)
3x=33 (subtract 6x)
x=11 (divide by 3)