Answer:
m<SQP=124°
Step-by-step explanation:
Hi there!
We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)
we need to find m<SQP (given as x+72°)
exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).
that means that m<SQP=m<R+m<S (Exterior angle theorem)
substitute the known values into the equation
x+72°=90°+34° (substitution)
combine like terms on both sides
x+72°=124° (algebra)
subtract 72 from both sides
x=52° (algebra)
however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP
m<SQP=x+72°=52°+72°=124° (substitution, algebra)
Hope this helps!
Answer:
12
Step-by-step explanation:
A rhombus is a parallelogram with all four sides equal.
Its diagonals are perpendicular.
Each of the triangles formed by the diagonals and the sides are congruent, so the area of the rhombus is 4 times the area of one of the triangles.
Since the short diagonal is given as 4, each of the triangles can be viewed as having a base of 2. Each triangle's height, h, then is one half the length of the long diagonal.
The are of one of the triangles is 1/2 (base)(height)=(1/2)(2)h
The area of the rhombus is then
4(1/2)(2)h=24
Solving for h gives
h=6
This makes the length of the long diagonal 2h=12
4¹/₃x = ⁵/₁₂x - 6
3¹¹/₁₂x = -6
x = -1²⁵/₄₇