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butalik [34]
3 years ago
8

?? Choose the equation of a line with a slope of 3/4 and passing through the point (8,5). y = (3/4)x - 5 y = (3/4)x + 5 y = (3/4

)x + 1 y =(3/4)x - 1
Mathematics
1 answer:
prisoha [69]3 years ago
5 0

Answer:

d. y = 3/4x - b

Step-by-step explanation:

Use the y = mx + b formula to solve the equation. Plug in the known values in to this. After you have done that, you should get:


y = 3/4x - 1



Sorry if i didn't explain well. Hope it helps! :)

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Samuel makes a dozen of mini cupcakes using 5/8 ​ cups of sugar, 3 cups of chocolate chips and 1/2 cup of butter. If each cupcak
baherus [9]

I don't what form of measurement to use (like grams, cusp, etc.) but I'm pretty sure it'd be cups

I think it's 5/96 or .05208333

So, 5/8 is .625. Dividing that up in throwing it into 12 cupcakes.

8 0
2 years ago
Hey everyone! Please help me figure this out...
shepuryov [24]

Answer:

See below

Step-by-step explanation:

0.82=82/100=82%

22%=22/100=0.22

3/4=0.75=75/100=75%

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Hope this helps!

5 0
3 years ago
Read 2 more answers
At 3:30 in the afternoon in mid-September the Kimball Tower casts a shadow about 290 feet long when the sun's rays come down at
ioda

Answer:

203 feet.

Step-by-step explanation:

Please find the attachment.

Let h represent the height of the building.

We have been given that at 3:30 in the afternoon in mid-September the Kimball Tower casts a shadow about 290 feet long when the sun's rays come down at an angle about 35 degrees above the horizontal.    

We know that tangent relates opposite side of a right triangle to its adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

Upon substituting our given values in above formula, we will get:

\text{tan}(35^{\circ})=\frac{h}{290}

290*\text{tan}(35^{\circ})=\frac{h}{290}*290

290*0.70020753821=h

h=290*0.70020753821

h=203.0601860809

h\approx 203

Therefore, the building is approximately 203 feet high.

 

3 0
3 years ago
How many brands of raisin bran are shown in the table?
Firlakuza [10]
I can’t see the table. Include an attachment?
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3 years ago
A landscaper has enough cement to make a patio with an area of 150 Sq ft. The homeowner wants the length of the patio to be 6 ft
Natasha_Volkova [10]
A=lw=150\\l=w+6\\(w+6)w=150\\w^2+6w=150\\w^2+6w-150=0\\w=\frac{-b+-\sqrt{b^2-4ac}}{2a}\\w=\frac{-(6)+-\sqrt{(6)^2-4(1)(-150)}}{2(1)}\\w=\frac{-6+-\sqrt{36+600}}{2}\\w=\frac{-6+-\sqrt{636}}{2}\\w=\frac{-6+-2\sqrt{159}}{2}\\w=-3+-\sqrt{159}>0\\w=-3+\sqrt{159}\\\\l=(-3+\sqrt{159})+6\\l=3+\sqrt{159}

Width = -3 + sqrt(159)
Length = 3 + sqrt(159)
4 0
3 years ago
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