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egoroff_w [7]
3 years ago
11

I need help with this question!!!

Mathematics
2 answers:
mixer [17]3 years ago
6 0

Hi!


Its me again


what you do is you move all the numbers on one side of the equal sign and the variable on the other side, when you move the numbers the switch signs


so it will be -2k=4-8

-2k=-4

switch the signs

2k=-4

k=-2

CaHeK987 [17]3 years ago
3 0

K is equal to 2.

You have to move the 4 to the other side and change the addition sign to subtraction. After that, you have to subtract 8 and 4 which will give you 4 and 4 divided by 2 is 2 which means that k equals 2.

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V125BC [204]

Answer:

C. 15

Step-by-step explanation:

The following proportional can be set-up for the figure given:

\frac{x + 3}{x} = \frac{10 + 2}{10}

Solve for x

\frac{x + 3}{x} = \frac{12}{10}

\frac{x + 3}{x} = \frac{6}{5}

Cross multiply

5(x + 3) = x(6)

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15 = x

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3 years ago
BESTIES PLEASE HELP ASAP WILL GIVE POINTS AND BRAINLIEST. Express as a trinomial (2x-6) (x-4)
zaharov [31]

Answer:

2x² - 14x + 24

Step-by-step explanation:

Use the FOIL method (First, Outside, Inside, Last).

First, multiply the first term of both parenthesis:

2x * x = 2x²

Next, multiply the outside terms of both parenthesis:

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Then, multiply the inside terms of both parenthesis:

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Finally, multiply the last terms of both parenthesis:

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Combine like terms:

2x² - 8x - 6x + 24

2x² (-8x - 6x) + 24

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2x² - 14x + 24 is your answer.

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4 0
3 years ago
Read 2 more answers
Please help they are separate questions please help me with this!
monitta

Answer: Mary makes $1160, Steven makes $142.50

Step-by-step explanation:

Facts

MARY

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The first question about Mary asks how much commision she makes. To find that, lets find 8% of 14,500

8% of 14,500= 0.08x14,500= 1160

Therefore, Mary makes $1,160 in commision.

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6 0
2 years ago
Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit
ikadub [295]

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=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}

3 0
3 years ago
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Tom [10]
I can help, but what are you exactly trying to do here?
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