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aniked [119]
4 years ago
6

1/3 (q + 3) = 5 What is Q? Explain why 1/3 is a fraction

Mathematics
2 answers:
Harrizon [31]4 years ago
7 0

Answer:

q=12.

Step-by-step explanation:

1/3(q+3)=5 can be translated to (q+3)/3=5.

Multiply each side by 3 to get q+3=15.

Subtract 3 from each side to get q=12.

Can you explain what you mean by "Explain why 1/3 is a fraction?"

Scilla [17]4 years ago
5 0

Answer:

Assuming Q is q, q = 12.  1/3 is a fraction since it is a ratio of two whole numbers.

Step-by-step explanation:

For this problem, we need to understand two things.  (1)  q is the unknown variable of this equation.  (2) The definition of a fraction is a "numerical quantity that is not a whole number" -Oxford Dictionary which can also be stated mathematically as a ratio of two whole numbers.

First, let's explain why 1/3 is a fraction.  In the numerator, we have the whole number 1, and in the denominator, we have the whole number 3.  Mathematically, 1/3 is a fraction since it is a ratio of two whole numbers.  Alternatively, we can say it's a non-whole numerical quantity.  In this case, 0.33 repeating.

Second, let's solve for our unknown variable q:

1/3 ( q + 3 ) = 5

1/3 ( q + 3 ) * 3 = 5 * 3

q + 3 = 5 * 3

q + 3 = 15

q + 3 - 3 = 15 - 3

q = 15 - 3

q = 12

Hence, the value of q is 12.

Cheers.

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c) When we increase the sample size we increse the probability of rejection of the null hypothesis since the z score tend to increase when the sample size increase.

Step-by-step explanation:

Data given and notation  

Part a: If the sample consists of n=16 individuals, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha = 0.05.

\bar X=31.3 represent the sample mean  

s=3 represent the sample standard deviation  

n=16 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 30, the system of hypothesis are :  

Null hypothesis:\mu = 30  

Alternative hypothesis:\mu \neq 30  

Since we don't know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{31.3-30}{\frac{3}{\sqrt{16}}}=1.733  

P-value  

First w eneed to find the degrees of freedom given by:

df=n-1=16-1 =15

Since is a two-sided test the p value would given by:  

p_v =2*P(t_{15}>1.733)=0.104  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the we don't have a significant effect for the new treatment at 5% of significance.  

Part b: If the sample consists of n=36 individuals, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha = 0.05.

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{31.3-30}{\frac{3}{\sqrt{36}}}=2.6  

P-value  

First w eneed to find the degrees of freedom given by:

df=n-1=16-1 =15

Since is a two-sided test the p value would given by:  

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When we increase the sample size we increse the probability of rejection of the null hypothesis since the z score tend to increase when the sample size increase.

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