For a horizontal line, gradient is zero;
y=mx+c
since m=0
y=c
Replacing for y from given point;
-1=c
c=-1
y-1
Use distance formula, sqrt[(y2-y1)^2+(x2-x1)^2].
sqrt[(1-4)^2 + (6-1)^2]
= sqrt(34)
Answer:
-66
Step-by-step explanation:
-33 +(-33)
ok so if you add a negative number then you are pretty much subtracting a positive number
-33 - 33 = -66