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2 years ago

The sum of three consecutive odd numbers is one hundred fifty-nine

1 answer:

8 0

First remember that sum means to add. now think about the equation. we need to find 3 numbers that equal 159 when added together. And they are all consecutive odd numbers. so let's call the first number X. the second number would be X+2 since we have to jump over 1 even number. The third number would be X+4 since we have to jump over 2 even numbers. so now an equation to represent this would be X+(X+2)+(X+4)=159. Add like terms, and remember order of operations. if you need help getting the answers leave me a comment.

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PLSSSSS HELP WILL GIVE BRAINLIEST

11111nata11111 [884]

Answer:

a = -12

b = -4

c = 4

d = 3

e = -3

Step-by-step explanation:

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2 years ago

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Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .

Katyanochek1 [597]

Answer:

a)The component form is

$\vec {QP}=\binom{ - 1}{ - 8}$

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

$\vec {QP}=\vec {OP}-\vec{OQ}$

We substitute the position vectors to get:

$\vec {QP}=\binom{ - 8}{7} - \binom { - 7}{15}$

We subtract the corresponding components to obtain:

$\vec {QP}=\binom{ - 8 - - 7}{7 - 15}$

This gives:

$\vec {QP}=\binom{ - 8 + 7}{7 - 15}$

This simplifies to:

$\vec {QP}=\binom{ - 1}{ - 8}$

The magnitude of a vector in the component form:

$\binom{x}{y}$

$\sqrt{ {x}^{2} + {y}^{2} }$

This means:

$|\vec {QP}|= \sqrt{ {( - 1)}^{2} + {( - 8)}^{2} }$

This simplifies to:

$|\vec {QP}| = \sqrt{ 1 + 64 }$

$|\vec {QP}| = \sqrt{ 65 }$

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>

7 0

2 years ago

PLEASE HELP ASAP!

brilliants [131]

Answer:

-4,790

Step-by-step explanation:

60 x 389 = 23,340

18,550 - 23,340 = -4,790

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2 years ago

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Darya [45]

Answer:

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Step-by-step explanation:

The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle to the length of the longest side of the triangle (the hypotenuse).

Fixed point: 0

Critical point: kπ + π/2

Inflection point: kπ hope this helps you :)

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2 years ago

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Nikolay [14]

Answer:

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Step-by-step explanation:

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2 years ago