Answer: f(x)=567(1/3)^x
Step-by-step explanation:
At x = 0 y = 567
at x = 1 y = 567 - 567(1/3)
at x = 2 y = 567 - 567(1/3)(1/3)
at x = 3 y = 567 - 567(1/3)(1/3)(1/3
Answer:
50
Step-by-step explanation:
They need to sell 50 of them in order to raise $1000. Its simple math all you have to do is divide 1000 by 20 and poof you have the answer.
Answer:
- f¯¹(x) =9x+18, for the pictorial(image) question
- what is the send question is it asking derivative or inverse
- If it is inverse f¯¹(x)=-x-2 as it is
- Or if it is derivative f'(x)=-1
Step-by-step explanation:
<h2>
For the image question f(x)=1/9x-2,f¯¹(x)=?</h2>
- f(x)=1/9x-2............given
- y=1/9x-2................swapping f(x) by y to Easily write
- x=1/9y-2................interchanging x and y
- 1/9y-2=x................changeling side of equation
- 9(1/9y-2)=(x)9.......multiplying both sides by 9 to override the fraction on the right side
- y-18=9x
- y=9x-18.................Return to where it were
- <em><u>f¯¹(x)=9x+18</u></em>..........swap back f¯¹(x) in the y
<h2>
For the question f(x)=-x-2,f¯¹(x)=?</h2>
- following the ☝️ arrangement
- y=-x-2
- x=-y-2
- -y-2=x
- -y=x+2
- y=-x-2
- f¯¹(x)=-x-2
The domain: {-4; -1; 0; 2; 4}
The range: {-2; 0; 1; 3}
Yes. The relation is a function.
