Answer:
16.4
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The given system of equations 4x + 4y = 32 and 3x + 24 = 3y has only one solution
<u>Solution:</u>
Given, system of equations are:
4x + 4y = 32 ---- eqn (1)
3x + 24 = 3y ----- eqn (2)
We have to determine whether the system has one solution, no solution, or infinitely many solutions.
Now let us solve the given system of equations to determine.
Now, eqn (1) can be written as,
4(x + y) = 32
x + y = 8
x = 8 – y
So, substitute "x" value in eqn (2) to get the value of "y"
3(8 – y) + 24 = 3y
24 – 3y + 24 = 3y
48 = 3y + 3y
y = 8
Then, x = 8 – 8 = 0
Hence we got x = 0 and y = 8
Hence, the given system of equations has only one solution (x, y) = (0, 8)
Answer:
53 54 55
Step-by-step explanation:
Consecutive Integers are integers that go one after the other unless explained otherwise, so 53, 54 and 55 add up to 162.
Izzy used 2 9/10 yards of rope for the tire swing
Hope this helps :)
