PLEASE HELP WILL GIVE BRAINLIEST, 5 STAR RATING, THANKS.

Mathematics

1 answer:

devlian [24]2 years ago

5 0

Answer:

Simple Algebra

Step-by-step explanation:

First set the equations equal to each other. Second, combine like terms. You should now have 10 = x. Now substitute the ten for the x and solve.

You might be interested in

In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle. Find the measure

soldi70 [24.7K]

Given:

In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.

To find:

The measures of the 2 acute angles of the triangle.

Solution:

Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,

$x+(2x+12)+90=180$

$3x+102=180$

$3x=180-102$

$3x=78$

Divide both sides by 3.

$x=\dfrac{78}{3}$

$x=26$

The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:

$2x+12=2(26)+12$

$2x+12=52+12$

$2x+12=64$

Therefore, the measures of two acute angles are 26° and 64° respectively.

8 0

2 years ago

X^2/9+2y/7 help me solve

vfiekz [6]

So firstly, we have to find the LCD, or lowest common denominator, of 9 and 7. To do this, list the multiples of 9 and 7 and the lowest multiple they share is going to be your LCD. In this case, the LCD of 9 and 7 is 63. Multiply x^2/9 by 7/7 and 2y/7 by 9/9:

$\frac{x^2}{9}\times \frac{7}{7}=\frac{7x^2}{63}\\\\\frac{2y}{7}\times \frac{9}{9}=\frac{18y}{63}\\\\\frac{7x^2}{63}+\frac{18y}{63}$