We are given
Andre rode his bike at a constant speed he rode 1 mile in 5 minutes
Firstly, we will find constant speed
In 5 minutes , distance travelled =1 miles
so, we get speed

Let's assume T is time in minutes
D is the distance in miles
we know that

so, we can plug value
and we get

so, we get
...............Answer
Answer:
a
The estimate is 
b
Method B this is because the faulty breaks are less
Step-by-step explanation:
The number of microchips broken in method A is 
The number of faulty breaks of method A is 
The number of microchips broken in method B is 
The number of faulty breaks of method A is 
The proportion of the faulty breaks to the total breaks in method A is


The proportion of the faulty to the total breaks in method B is

For this estimation the standard error is

substituting values


The z-values of confidence coefficient of 0.95 from the z-table is

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as
![K = [p_1 - p_2 ] \pm z_{0.95} * SE](https://tex.z-dn.net/?f=K%20%3D%20%5Bp_1%20-%20p_2%20%5D%20%5Cpm%20z_%7B0.95%7D%20%2A%20SE)
substituting values
![K = [0.08 - 0.07 ] \pm 1.96 *0.0186](https://tex.z-dn.net/?f=K%20%3D%20%5B0.08%20-%200.07%20%5D%20%5Cpm%201.96%20%2A0.0186)

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

Answer: 2584
Step-by-step explanation:
We can find N with 2584 and 4181.
4181 - 2584
= 1597
We can also check our answer by adding 1597 and 987
1597 + 987
= 2584
Answer:
9:100
Step-by-step explanation:
Turn 9% into a fraction by putting it over a hundred:
9/100
Then simply change the '/' into ':'
If this were another fraction, let's say, 4/6, then you'd put it in simplest form, which is 2/3 = 2:3
Answer:
The series 1/5, 2/15, 4/45, 8/135... converges and sums up to 3/5
Step-by-step explanation:
Consider the infinite geometric series
1/5, 2/15, 4/45, 8/135...
With first term, a=1/5
common ratio, r = ⅔
The series converge because the common ratio, |r|<1.
The sum to infinity of a geometric series, S= a/(1-r)
S= 1/5 ÷ (1-⅔) = 1/5 ÷ 1/3 = 3/5
Therefore, the geometric series 1/5, 2/15, 4/45, 8/135... sums up to 3/5.