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laiz [17]
3 years ago
6

Estella buys 1.8 pounds if walnuts for a total if $5.04 she solves the equation 1.8p=5.04 to find the price p in dollars of one

pound of walnuts what does one pound of walnuts cost?
Mathematics
1 answer:
Drupady [299]3 years ago
8 0

Answer: $2.08

Step-by-step explanation:

5.04 divided by 1.08 is 2.08.

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What is .246 repeating (46 is repeating) as a fraction?
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Which of the following sets of numbers could be the lengths of the sides of a triangle? A. 81 mm, 7 mm, 6 mm B. 81 mm, 7 mm, 72
Lisa [10]
We know that
The triangle inequality<span> states that for any </span>triangle, t<span>he sum of the lengths of any two sides of a </span>triangle<span> is greater than the length of the third side
</span>so
case <span>A. 81 mm, 7 mm, 6 mm 
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case </span><span>B. 81 mm, 7 mm, 72 mm
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case </span><span>C. 81 mm, 7 mm, 88 mm
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case </span><span>D. 81 mm, 7 mm, 77 mm
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the answer is the option
</span>D. 81 mm, 7 mm, 77 mm
3 0
2 years ago
Can someone help me out? (Show work on how to solve)
belka [17]

Answer:

dghggjj

Step-by-step explanation:

s gm knfc JC. jz. jz. .xx nkcmxd I nt☺️️

8 0
3 years ago
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PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The
Nookie1986 [14]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}

<h3><u>Step-by-step explanation:</u></h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

  • Radius of smaller circle be r .
  • Radius of smaller circle be r .
  • Area of shaded region be \bf Area_{shaded}

\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2  \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2)  \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2]  \\\\\bf\implies Area_{shaded}  = \pi [ 100cm^2-16cm^2]  \\\\\bf\implies Area_{shaded}  = \pi \times 84cm^2  \\\\\bf\implies Area_{shaded}  = \dfrac{22}{7}\times 84cm^2  \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}

<h3><u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>

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2 years ago
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