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ollegr [7]
4 years ago
8

What is the circumference (in inches) of a circle with radius of 5 inches? Use 3.14 for n.

Mathematics
2 answers:
Yuliya22 [10]4 years ago
6 0

Answer:

A. 31.4 in.

Step-by-step explanation:

Formula for the circumference:

C = dπ (d = 2r)

Therefore:

C = 10π

C = 10 · 3.14

C = 31.4 in.

Furkat [3]4 years ago
5 0

Answer:

A: 31.4 in

Step-by-step explanation:

Use the equation C = 2πr to solve your problem.

Since you are given the radius <em>r </em>you only need to plug in 5 in. to r and calculate it on the calc. When you multiply everything together you should get 31.4 in.

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Kryger [21]
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2+1 is 3 
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check your answer by plugging it in
-1*-3 is 3 
so - 3+1 world be 4 which is where the 2 is on the number line because it goes into negatives 

answer is x= -1
3 0
4 years ago
Sin -cos+1/sin+cos-1 =sec+tan prove
EleoNora [17]
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3 0
3 years ago
The rectangle below has an area of 81- x^2 square meters and a width of 9 - x meters
sveta [45]

Answer:

The width would be 9 + x

Step-by-step explanation:

In order to find this, we must first factor the area. This will give us two things that are being multiplied together.

81 - x^2 = (9 - x)(9 + x)

Since the area is the length times the width and the width is x - 9, we know the length must be x + 9

6 0
4 years ago
A plane has an airspeed of 111 km/h. It is flying on a bearing of 79 degrees while there is a 25 km/h wind out of the northeast​
qwelly [4]

Answer: Ground Speed = 91 km/hr,   Bearing = 189°

<u>Step-by-step explanation:</u>

Step 1: Draw a picture (see attached) to determine the angle between the given vectors.  Notice that I moved the wind vector 180° <em>so the head of the wind vector would line up with the tail of the plane vector. </em>This created an angle of 34° between the plane and wind vectors. <em>Why?</em>

  • the dashed line is 45°
  • 79° (plane) - 45° (wind) = 34°

Step 2: Solve for the length of the resultant vector using Law of Cosines

<em>c² = a² + b² - ab cos C</em>

c² = (111)² + (25)² - (111)(25) cos 34°

c² = 12,946 - 4601

c² = 8345

c = 91

Ground speed is 91 km/hr

Step 3: Solve for the bearing of the resultant vector using Law of Sines

\dfrac{sin\ A}{a}=\dfrac{sin\ C}{c}

\dfrac{sin\ A}{25}=\dfrac{sin\ 34}{91}

sin\ A=\dfrac{25\ sin\ 34}{91}

A=sin^{-1}\bigg(\dfrac{25\ sin\ 34}{91}\bigg)

A = 9°

<em>Reminder that we moved the wind vector 180° to create the resultant vector so we need to add 180° to our answer.</em>

Bearing = A + 180°

              =  9° + 180°

              = 189°


7 0
3 years ago
Does anyone know the answer to these two problems?
Nady [450]

Answer:

8) -8, -9

9) 4, $ \frac{1}{2} $

Step-by-step explanation:

8) x² + 12x + 27

Solutions of a polynomial means the values of $ x $ such that the polynomial becomes zero. $ i.e., y = 0 $.

We use the following formula to determine the solutions of a quadratic equation of the form: $ ax^2 + bx + c = 0 $

    $ \implies x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

In this equation, $ a = 1; b = 12; c = 27 $

Substituting in the formula, we have:

$ x = \frac{-12 \pm \sqrt{144 - 108}}{2} $

$ \implies x = \frac{-12 \pm 6}{2} $

Taking 2 common outside we get:

$ x = - 6 \pm 3 $

Therefore, we get two solutions viz, x = -3, -9.

9) 2x² - 9x + 4 = y

X- intercepts of a polynomial means the value of x such that y = 0. It means the roots of the polynomial.

Solving the equation using the formula above, we get:

$ x = \frac{-(-9) \pm \sqrt{81 - 32}}{2(2)} $

$ \implies x = \frac{9 \pm 7}{4} $

The values of x = 4, $ \frac{1}{2} $.

Hence, the answer.

8 0
4 years ago
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