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jeka94
3 years ago
15

Lin ran 2 3/4 miles in 2/5 of an hour, Noah ran 8 2/3 miles in 4/3 of an hour, how far would Lin run in 1 hour?

Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

6\frac{7}{8}\ miles

Step-by-step explanation:

Given that Lil's distance in 2/5 hrs is 2 3/4hrs

-Let x be the distance ran in 1 hr.

#We equate and cross multiply to solve for x as follows:

\frac{2}{5}\ hrs=2\frac{3}{4}\\1\ hr=x\\\\\therefore x=2\frac{3}{4}/\frac{2}{5}\\\\=6\frac{7}{8}\ miles

Hence, Lil can run 6 7/8 miles in 1 hr.

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Paulo catches a 7.45 am tram to school. During a period of 79 days, he arrives at school on time 53 occasions. Estimate the prob
lawyer [7]

Answer:

<em>On time: 0.67</em>

<em>Late: 0.33</em>

Step-by-step explanation:

<u>Probabilities</u>

One approach to estimating the probability of occurrence of an event is to record the number of times that event happens (e) and compare it with the total number of trials (n).

The probability can be estimated with the formula:

\displaystyle P=\frac{e}{n}

And the probability that the event doesn't occur is

Q = 1 - P

Paulo arrives on time to school e=53 times out of n=79 times. The probability that he arrives on time is:

\displaystyle P=\frac{53}{79}

P = 0.67

And the probability he arrives late is:

Q = 1 - 0.67 = 0.33

4 0
3 years ago
make a hypothesis about the sum of the interior angles of any trangle. Explain why your hypothesis works for all triangles
lakkis [162]

Answer:

The sum of the three angles of any triangle will always be 180 degrees because when all three angles are put together, they form a straight line.

Step-by-step explanation:

I did it on Edgenuity

8 0
3 years ago
Reagan used 1,221 sq ft of wrapping paper to wrap gifts for everyone in her class. If each gift used the same amount of wrapping
ipn [44]
She used 1221 wrapping paper for 21 gifts, so to find the individual amount, you would do:
1221/21
She used about 58.143 ft² of wrapping paper for each gift.
8 0
3 years ago
Read 2 more answers
There are 9 movies ranked on the summer's "must see movie list." What is the probability that you guess the summer's top two mus
oee [108]

Answer:

1/36 = 0.0278 = 2.78% probability that you guess the summer's top two must see movies if you randomly guess

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question, the order in which the movies are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes:

Top two movies, so only one outcome, which means that D = 1

Total outcomes:

Two movies from a set of 1. So

T = C_{9,2} = \frac{9!}{2!(9-2)!} = 36

Probability:

p = \frac{D}{T} = \frac{1}{36} = 0.0278

1/36 = 0.0278 = 2.78% probability that you guess the summer's top two must see movies if you randomly guess

7 0
2 years ago
Show that the given general solution satisfies the given differential equation, showing all work carefully. Do NOT do this by so
shepuryov [24]

Explanation:

Differentiating the solution, we have ...

  y' = c1 +8c2x^7

  y'' = 56c2x^6

Putting this into the DE, we have ...

  x^2y'' -8xy' +8y = 16 . . . . . . . different from your problem statement

  x^2(56c2x^6) -8x(c1 +8c2x^7) +8(c1x +c2x^8 +2) = 16

  56c2x^8 -8c1x -64c2x^8 +8c1x +8c2x^8 +16 = 16

  x^8(56c2 -64c2 +8c2) +x(-8c1 +8c1) +16 = 16

  0 +16 = 16 . . . . QED

4 0
3 years ago
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