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olya-2409 [2.1K]
3 years ago
15

Just How? (2a^2 c^4) ^-5 (c^-1 a^7)^6

Mathematics
2 answers:
WINSTONCH [101]3 years ago
6 0
Just how? (2a^2 c^4) ^-5 (c^-1 a^7)^6

ANSWER.

\boldsymbol {(2^2 \ c^4)^{-5} (c^{-1} \ a^7)^6}\\
\\
\boldsymbol {= 2^{-10} \ c^{-20} \ (c^{-1} \ a^7)^6}\\
\\
\boldsymbol {= 2^{-10} \ c^{-20} \ c^{-6} \ a^{42}}\\
\\
\boldsymbol {= 2^{-10} \ a^{42} \ c^{-26}}\\
\\
\boldsymbol {\dfrac{1}{2^{10}} \ a^{42} \ c^{-26}}\\
\\
\boldsymbol {\dfrac{1}{2^{10}} \ a^{42} \ \dfrac{1}{c^{26}}}\\
\\
\\
\boldsymbol {\dfrac{1 \ \cdot \ 1 \ \cdot a^{42}}{2^{10} \ c^{26}}}\\
\\
\\
\boldsymbol {= \dfrac{a^{42}}{1024c^{26}} \ \checkmark.} 

\boldsymbol {\dfrac{a^{42}}{1024c^{26}} \Leftarrow \underline{Answer}}

REGARDS!
skelet666 [1.2K]3 years ago
4 0
Express with a positive exponent
2∧5 a∧-10 c∧-20 × c∧-6 a∧42
Evaluate the power
1/2∧5×a∧-10 c∧-20 × c∧-6 a∧42
Calculate the product
1/32a∧-10 c∧-20 × c∧-6 a∧42
Express with a positive exponent
1/32a∧32 c∧-26
Calculate the product
1/32a∧32 × 1/c∧26
Answer

a∧32/32c∧26
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b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925

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y = 0.939X1 + 0.309X2 + 31.733

For x1 ( age ) =39, and  x2(weight) =143

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attached is the Tabular calculation of the required values needed for estimated regression equation

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Someone please help me I suck @ simplifying thank you
dsp73

To solve this question, you would need to find the common denominator among the 2 fractions. In this case it would be

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Step-by-step explanation:

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